2(x-4)^2+41=12

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Solution for 2(x-4)^2+41=12 equation: 



2(x-4)^2+41=12

We move all terms to the left:

2(x-4)^2+41-(12)=0

We add all the numbers together, and all the variables

2(x-4)^2+29=0

We move all terms containing x to the left, all other terms to the right

2(x-4)^2=-29

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